### Thermal Conductivity Calculator :

Enter the thermal conductivity calculator lets you calculate the thermal conductivity constant (λ) in W/(m·K), Temperature difference (ΔT) in °C, Distance (Δx) in meters(m), Heat flux (q) in W/m²,and you get the calculator.

### Thermal Conductivity Formula :

Thermal conductivity formula is K_{(wm-1 k-1)} in watts per meter^{-1} and Kelvin^{-1} is equal to the amount of heat transferred through the material Q_{(j/s)} in joule per second and multiply the length L_{(m)} in meter and divided by the area of the body A_{(m2)} in meter^{2} and multiply the temperature difference ΔT_{(k)} in Kelvin. Hence the Thermal conductivity formula can be written as,

**K _{(wm-1 k-1)}=Q_{(j/s)}*L_{(m)}/A_{(m2)}* ΔT_{(k)}**

where,

K→ thermal conductivity in wm^{-1} K^{-1}

Q→ amount of heat transferred through the material in j s^{-1}

A→ area of the body in m^{2}

ΔT→ temperature difference in k

### Sample Problems :

### Problem 1:

Calculate the thermal conductivity value? In a amount of heat 0.40 j/s and length 2.50 m and area 80 m^{2 } and temperature 50 k.

### Answer:

Q=0.40 j/s

L=2.50m

A=80 m^{2}

T=50K

K_{(wm-1 k-1)}=Q_{(j/s)}*L_{(m)}/A_{(m2)}* ΔT_{(k)}

K=0.40*2.50/80*50

K=0.625 W m ^{-1} k^{-1}

### Problem:2

Calculate the thermal conductivity value? In a amount of heat 0.45 j/s and length 3.80 m and area 40 m^{2 } and temperature 25k.

### Answer:

Q=0.45 j/s

L=3.80m

A=40 m^{2}

T=25K

K_{(wm-1 k-1)}=Q_{(j/s)}*L_{(m)}/A_{(m2)}* ΔT_{(k)}

K=0.45*3.80/40*25

K=1.06 W m ^{-1} k^{-1}