Magnetic Field Strength Formula and Sample Sums

Magnetic Field Strength Formula :

Magnetic Field strength Formula  is magnetization of the magnitude B(A/m) in Ampere per meter is equal to product of permeability of free space μ0(m/A) in meter per Ampere and multiply the magnitude of the electric current I (A) in Ampere and divided by the two pi 2 π and multiply the distance r(m) in meter. Hence the Magnetic Field Strength Formula can be written as

B(A/m)0(m/A)*I (A)/2 π*r(m)

Where,

B→ magnetization of the magnitude A/m

μ0 →Permeability of free space 4 μ*10-7 T m/A

I→ Magnitude of the electric current  in A

R→ distance in m

Sample Sums :

Sums 1:

Calculate the magnetic field strength inside a solenoid which is 2 m long and has 2000 loops. Furthermore, it carries a 1600 A current?

Solution :

In order to Find the magnetic field strength inside the solenoid, one must use B= μ0  Ni .Furthermore one must note the number of loops per unit length

n=N/r=2000/2=1000m-1=10cm-1

Now one must substitute known values

B= μ0  Ni

=(4 π 10-7 m/A) (1000m-1)(1600A)

=2.01T

Sums 2:

Calculate the magnetic field strength inside a solenoid which is 3 m long and has 3000 loops. Furthermore, it carries a 1200 A current?

Solution :

In order to Find the magnetic field strength inside the solenoid, one must use B= μ0  Ni .Furthermore one must note the number of loops per unit length

n=N/r=3000/3=1000m-1=10cm-1

Now one must substitute known values

B= μ0  Ni

=(4 π 10-7 m/A) (1000m-1)(1200A)

=1.501T

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