## Force of Attraction Formula :

Force of attraction formula F_{g(N) }in Newton_{ }is equal to product of the gravitational constant G _{(Nm2/kg2) }in Newton meter^{2}/Kilogram^{2} and the mass of the object m_{1 and }m_{2 } in kilogram per second divides by square the distance between two object is r _{(m) }in meter. Hence the force of Attraction formula can be written as,

**F _{g(N)}=G _{(Nm2/kg2) }*m_{1} _{(kg/s) }*m_{2(kg/s)} / r^{2} _{(m)}**

Where,

F → force of attraction in Newton

G→ gravitational constant (6.67×10^{-11 }Nm^{2 }/Kg^{2})

The mass of object 1 is m_{1 } in kg/s

The mass of object 2 is m_{2} kg/s

The distance between two objects → r

This formula aids out in calculating the force acting amongst any two bodies having a greater mass since in smaller masses this force is insignificant.

## Sample Sums :

### Sum 1 :

Calculate the gravitational force acts amongst two bodies of masses 40,000kg and 80,000kg parted by a distance of 80m ?

### Solution :

Known,

Mass m_{1}=40000

Mass m_{2} =80000kg

radius r=80m

Gravitational constant G=6.67×10^{-11 }Nm^{2 }/Kg^{2}

The force due to gravity is given by

F_{g}=Gm_{1 }m_{2} / r^{2}

F=6.67×10^{-11 }Nm^{2 }/Kg^{2}×40000×80000/80^{2}

F=3.35×10^{-5} N

### Sum 2:

Calculate the gravitational force acting between them ? In a body of weight 40kg is 4m far away from the body of weight 80kg.

### Solution :

Known,

Mass m_{1 }=40kg

Mass m_{1} =80Kg

Radius r=4m

Gravitational constant G=6.67×10^{-11 }Nm^{2 }/Kg^{2}

F_{g}=Gm_{1 }m_{2} / r^{2}

F=(6.67×10^{-11 })×40×80/4^{2}

F=1.334×10^{-8} N