## Deceleration Formula :

Anytime we are in a vehicle and we feel moving forward relative to the vehicle, then we are decelerating. Here, deceleration is a special case of acceleration whereby it only applies to objects slowing down

**Deceleration = Final time – Initial time / Time taken**

Deceleration a_{(m/s2)} in meter per second square is equal to the product of the final velocity v_{(m/s)} in meter per second is subtracted by initial velocity u_{(m/s)} in meter per second is divided by time taken t_{(s) }in second. Hence the Deceleration Formula has been written as,

**a _{(m/s2)} = v_{(m/s)} – u_{(m/s)} / t_{(s) }**

Deceleration a_{(m/s2)} in meter per second square is equal to the product of the final velocity v_{(m/s)} in meter per second is subtracted by initial velocity u ^{2}_{(m/s)} in meter per second is divided by distance covered 2s_{(m).}in second. Hence the Deceleration Formula has been written as,

**a _{(m/s2)} = v^{2}_{(m/s)}_{ }– u^{2 }_{(m/s)} / 2s_{(m).}**

Where,

v →final velocity in (m/s).

u → initial velocity in (m/s).

t → time taken in (s).

s →distance covered in (m).

Deceleration Formula is used to calculate the deceleration of the given body in motion. It is expressed in meter per second square (m/s^{2}).

## Sample Examples:

### Example 1:

Calculate the deceleration produced by brakes? In a automobile moving with a uniform velocity of 64 Kmph is brought to rest in travelling a distance of 6 m.

### Solution :

Given: Initial velocity u = 64 Kmph,

Final velocity v = 0

Distance covered s = 6m

We know that v^{2} = u^{2} + 2as

Deceleration a = v^{2} – ^{ }u^{2} / 2s

= – (64000 )^{2} / 2(6)

a = – 122.88 * 10^{6 }m/s^{2}.

### Example 2:

Calculate the deceleration value if the initial velocity is 10 m/s for a time of 2 s.

### Solution :

We have,

u = 10

t = 2

Using the formula we have,

a = -u/t

= -10/2

= -5 m/s^{2}.