### What is Conduction?

The process of transferring energy from one particle of a medium to another by the particles being in direct contact with each other

An area of higher kinetic energy transfers heat energy to an area of lower kinetic energy. Faster particles collide with slower moving particles,

As a result, slow speed particles increase their kinetic energy.

It is a common form of heat transfer and takes place through physical contact. Conduction is also known as heat conduction or heat conduction.

### Conduction Formula :

Conduction Equation is the transfer of heat per unit time Q_{(Kj)} in kilojoule is eqvalt to the product of thermal conductivity of the body K_{(wm-1 k) }in watts per meter^{-1} kilo and multiply the area of heat transfer A_{(m)} in meter and multiply the is the temperature of the hot region T_{hot(0c ) }in degree Celsius and minus is the temperature of the cold region T_{cold(0c )} in degree Celsius and divided by the thickness of the body d. Hence the conduction formula can be written as

Q_{(Kj)}=[K_{(}_{wm-1 k) } *A_{(m)} (T_{hot(}_{0c}_{ )-}T_{cold(}_{0c}_{ )})]/d

Q→ transfer of heat per unit time in Kj

K→ thermal conductivity of the body in wm^{-1} k

A→ area of heat transfer in meter^{2}

T_{hot}→ temperature of the hot region in ^{0}c

T_{cold}→ temperature of the cold region in ^{0}c

D→ thickness of the body

### Example:

Calculate the conductivity 50 wm-1 k and Area 0.20 and temperature of the hot in0.80 ^{0}c and temperature of the gold 0.30 ^{0}c and thickness of the body 0.48 and Find the Transfer heat value?

### Answer:

K=50 wm-1 k

A=0.20 m^{2}

T_{hot}=0.80 ^{0}c

T_{cold}=0.30 ^{0}c

D=0.48

Q_{(Kj)}=[K_{(wm-1 k) } *A_{(m)} (T_{hot(0c )-}T_{cold(0c )})]/d

Q=50*0.20(0.80-0.30)/0.48

Q=5/0.48

Q=10.41Kj

The heat Transfer Q=10.41Kilo per joules

### Example:2

Calculate the conductivity 100 wm-1 k and Area 50 and temperature of the hot in200 ^{0}c and temperature of the gold 50 ^{0}c and thickness of the body 400 and Find the Transfer heat value?

### Answer:

K=100 wm-1 k

A=50 m^{2}

T_{hot}=200 ^{0}c

T_{cold}=50 ^{0}c

D=400

Q_{(Kj)}=[K_{(wm-1 k) } *A_{(m)} (T_{hot(0c )-}T_{cold(0c )})]/d

Q=100*50(200-50)/400

Q=750000/400

Q=1875Kj

The heat Transfer Q=1875 Kilo per joules