### Hydraulic Pressure Calculator :

Enter the first piston Area in cm², first piston Force in newton (N), second piston Area cm², second piston force in newtons(N), and you get the Liquid pressure in kilopascals(kPa).

### Pascal’s Law Formula:

Pascal’s law formula is the force applied to the first piston F_{1(N)} in Newton and divided by the area of the first piston A_{1(m2)} in meter^{2} is equal to the force applied to the second piston F_{2(N)} in Newton and divided by the area of the second piston A_{2(m2)} in meter^{2}. Hence the pascal’s law formula related to the Hydraulic pressure calculator can be written as

F_{1(N)}/A_{1(m2)}=F_{2(N)}/A_{2(m2)}

Where

F_{1}= force applied to the first piston in Newton

A_{1}=area of the first piston in meter square

F_{2}= force applied on the second piston in Newton

A_{2}= area of the second piston in meter square

The pressure of the liquid of the hydraulic press can be P=F_{1}/A_{1} or p=F_{2}/A_{2}

Another simple formulas are along the lines

D_{1 }= F_{2}/F_{1}*d_{2}

D_{1}=A_{2}/A_{1}*d_{2}

W=F_{1}*d_{1}=F_{2}*d_{2}

Where

D_{1}=distance at which the first piston has moved in meter

D_{2}= distance at which the second piston has moved in meter

W= total work done by the piston in in Joules per sec

### Example:1

Let us consider the Two pistons which have the hydraulic lift of 50 cm and 6 cm. Calculate the force at the larger piston when second piston gets 80N?

### Answer:

Given that

The radius of piston r=D/2

The diameter of smaller piston d_{1}=6cm

The diameter of the larger piston d_{2}=50cm

Area of smaller piston A_{1}= π(6/2)^{2 }=9 π

Area of larger piston A_{2}= π(50/2)^{2}

=625 π

Force of the larger piston f_{2}=(A_{2}/A_{1})XF_{1}

=(625 π)/( 9 π)*80

=54831 N

Therefore of the larger piston is 54831 N

### Example:2

Calculate the force 80N and area 20m^{2}.Find the light pressure value?

### Answer:

A_{1}=20 m^{2}

F_{1}=80N

P=F_{1}/A_{1}

P=80/20

Liquid pressure p=4.0 pa