### Hall Coefficient Calculator:

Hall Coefficient Formula:

Hall coefficient formula is RH_{(m3/c)} in meter3 per speed of the light is equal to the observed voltage difference voltage V_{(v)} in volts and multiply the thickness of the conductor t_{(s)} in second and divided by the current I_{(A)} in Ampere and multiply the magnetic field B_{(T)} in telsa . Hence the hall coefficient formula can be written as

RH_{(m3/c)} = V_{(v)}* t_{(s)} / (I_{(A)}*B_{(T)})

Voltage V=RH * I * B /t

Thickness t =RH *I * B/V

Current I= vt / (RH *B)

B=Vt /(RH *I)

Where

RH=is the hall coefficient in meter^3 per velocity of the carrier in meter per sec.

V = Observed voltage difference in volts

T = Thickness of the conductor

B = is the magnetic field

Hall coefficient gives the nature of the charge carriers and their concentration in the conductor. It formula is

RH =-1 / (nq)

Where

N=is the concentration of the carriers

Q=is the charge of a single carrier

### Example:1

Calculate the voltage 50v and current 48A and thickness 38.0m and magnetic field 25T.Find the hall coefficient value?

### Answer:

Voltage = 50 v

Current = 48 A

Thickness =38.0m

Magnetic field =25T

By using formula

RH_{(m3/c)} = V_{(v)}* t_{(s)} / (I_{(A)}*B_{(T)})

=50*38.0 / 48 * 25

=1.5833333 m^{3}/ c

### Example:2

Calculate the hall coefficient for 5*10^{28} atom /m^{3} in the copper block?

### Answer:

Given that

Nq = 5*10^{28} atom /m^{3}

Hall coefficient RH =-1 /(nq)

RH = -1 / (5*10^{28})

=-0.125 *10^{-9} m^{3}/c

Therefore, the hall coefficient is -0.125 *10^{-9} m^{3}/c