Graham’s Law Calculator, Formula, Calculation with Example

Graham’s Law Calculator:

Enter the Graham’s law Effusion in Rate of effusion of Gas 1 in mol/s, Rate of effusion of Gas 2 in mol/s, Molar mass of Gas 1 in g/mol, Molar mass of Gas 2 in g/mol , Graham’s law Diffusion in Rate of diffusion of Gas 1 in mol/s, Rate of diffusion of Gas 2 in mol/s, Molar mass of Gas 1 in g/mol and you get the Molar mass of Gas 2 in g/mol.

Rate of Effusion Calculator

Graham’s Law Formula:

Graham’s law formula is rate of effusion of the first gas Rate1 and divided by the rate of effusion of the second gas Rate 2 is equal to the root of the molar mass of gas 2 M2 (g mol-1 )  in gram mol-1 and divided by the molar mass of gas 1 M1(g mol-1 ) in gram per mol-1.Hence the Graham’s law formula can be written as

Rate1 / Rate 2 =√ M2 (g mol-1 ) / M1(g mol-1 )

M1 = molar mass of gas 1

M2 =  molar mass of gas 2

Rate1 = rate of effusion of the first gas

Rate2 =  rate of effusion of the second gas

½ m1*v12 =1/2 *m2*V22

v12 / V22 =√ M2 / M1

Rate1 / Rate 2 =√ M2 / M1

Example:1

Calculate the Inert gases Ne atoms how fast travel than Xe?

Answer:

Rate1 / Rate 2 =√ M2 / M1

=√f131.29 /20.18 =2.55

Ne is 2.55 times faster

Example:2

Calculate the molar mass of the unknown gas? In a unknown gas diffuses at a rate of 0.5 time that of nitrogen at the same temperatures and pressure.

Answer:

Rate1 / Rate 2 =√ M2 / M1

Rateunknown  / Rate N2 =√ M N2 / Munknown

0.5 =√ 28 g mol-1 / Munknown

Squaring on both sides

(0.5)2 =(√ 28 g mol-1 / Munknown)2

Munknown  =28 /0.25 =112 g mol-1

Leave a Comment