### Dift Velocity Calculator:

Enter the Current in ampere(A), Area in mm², Number density in ×10²⁸ carriers/m³ ,and Drift velocity in m/s.

With this drift velocity calculator you can calculate the velocity of any charged particle in a given object.

The drift velocity is a particle e.g. Electron, electron hole, is the average velocity that an ion attains in a material due to an applied voltage.

To determine the slip velocity, we need to know the number density,

It tells how many carriers are present within a unit volume of the material

It is usually expressed in carriers per cubic meter. In the text below, we have given the drift velocity equation and some simple calculations of the speed of an electron.

A simple procedure for finding the drift velocity of a charged particle is given below. Follow these steps and check the result.

Obtain the current, number density of electrons and surface

Multiply the area with the number density.

Divide the current flow by the output to get the slip velocity value.

### Drift Velocity Equation:

Drift velocity equation is V_{(m/s)} in meter per second is equal to the current flowing through the conductor I_{(A)} in Ampere and divided by the number of free electrons n_{(c/m3)} in carriers per meter^{3} and multiply the the cross – section area of the conductor A_{(m2)} in meter^{2} and multiply the the charge of an electron Q_{(c)} in coulomb’s. Hence the Drift velocity equation can be written as

V_{(m/s)}= I_{(A)} / (n_{(c/m3)} * A_{(m2)}* Q_{(c)})

The formula to find current is

I= n * V * A* Q

The formula to get area is A = I / (n * V *Q)

Where

V= drift velocity of the electrons in meter per second

I=current flowing through the conductor in ampere

N= number of free electrons in carriers /m^{3}

A= cross – section area of the conductor in m^{2}

Q= charge of an electron in coulomb’s

The number density in the calculator is nothing but the number of electrons per unit volume of the conductor.

### Example:1

Calculate the drift velocity of electrons? In a current of 2 A exists in a copper wire of cross- sectional area 2.0 mm^{2}.Assuming that the number density of electrons In wire is 15 *10^{28 } carriers/m^{3.}

### Answer:

Given that

Current flowing through wire I =2A

Cross – sectional Area A= 2mm^{2} =2 *10^{-6} m^{2}

Number density =15*10^{28} carriers /m^{3}

V= I / (n * A * Q )

= 2/ (15*10^{28 } * 2 *10^{-6} *2)

=3.333 *10^{24} m/s

### Example:2

Calculate the drift velocity of electrons? In acurrent of 6 A exists in a copper wire of cross- sectional area 9mm^{2}.Assuming that the number density of electrons In wire is 12*10^{28 } carriers/m^{3}.

### Answer:

Given that

Current flowing through wire I =6A

Cross – sectional Area A= 9mm^{2} =9*10^{-6} m^{2}

Number density =12*10^{28} carriers /m^{3}

V= I / (n * A * Q )

= 6 / (12*10^{28 } * 9 *10^{-6} *6)

=1.08 *10^{24} m/s