### Combined Gas Law Calculator :

Enter the Initial pressure (p₁) in Pa, Initial volume (V₁) in m³, Initial temperature (T₁) in K, Final pressure (p₂) in pa, Final volume (V₂) in m³, Final temperature (T₂) in K, Internal energy change (ΔU) in J, Work (W) in J, and you get the Heat (Q) 0 in j.

### Combined Gas Law Formula :

Combined gas law formula is pressure P1_{(pa)} in pascal is equal to the pressure p2_{(pa)} in pascal and multiply the volume v2_{(m3) }in meter^{3} and multiply the temperature T1_{(k)} in kelvin and divided by the temperature T2_{(m3)} in meter^{3} and multiply the volume v1_{(m3)} in meter^{3}.Hence the combined gas law formula can be written as

P1_{(pa)}=(p2_{(pa)}*v2_{(m3)* }T1_{(k)})/(T2_{(m3)}* v1_{(m3)})

### Derivation:

Pv/T=K

K=constant

P=pressure

V=volume

T=temperature

In order to compute the changes in temperature, pressure or volume a sample gas may suffer in certain conditions, the combined gas law can be written in the form detailed within the next rows;

P1*v1/T1=p2*v2/T2

The temperature is by default expressed in Kelvin but can also be specified in Celsius or Fahrenheit,a s the calculator applies the following rules to convert it to Kelvin

^{0}c to K=t^{0}c+273.15

^{0}F to k=(t^{0}F+459.67)*5/9

### Example:1

Calculate the pressure value? In a pressure 73pa, and volume 98m^{3},50 m^{3} and temperature 55k,65k.

### Answer:

P2=73pa

V2=50m^{3}

T1=55k

T2=65k

V1=98 m^{3}

By using formula

P1_{(pa)}=(p2_{(pa)}*v2_{(m3)* }T1_{(k)})/(T2_{(m3)}* v1_{(m3)})

P1=(73*50*55)/(65*98)

P1=31.5149 pa

### Example:2

Calculate the pressure value? In a pressure 25pa, and volume 24m^{3},75 m^{3} and temperature 33k,26k.

### Answer:

P2=25pa

V2=24m^{3}

T1=33k

T2=26k

V1=75 m^{3}

By using formula

P1_{(pa)}=(p2_{(pa)}*v2_{(m3)* }T1_{(k)})/(T2_{(m3)}* v1_{(m3)})

P1=(25*24*33)/(26*75)

P1=10.1538pa