### Boyle’s Law Calculator :

Enter the Boyle’s Calculator its Initial pressure (p₁) in pascals (Pa), Initial volume (V₁) in cubic meters(m³) and you get the calculator.

### Boyle’s Law Formula :

Boyle’s law formula is pressure of the gas P_{1 (pa) }in pascal and multiply the volume of the container V_{1(m2)} in meter2 is equal to the pressure of the gas p2_{(pa)} in pascal and multiply the volume of the gas V_{2(m2)} in meter^{2}.Hence the Boyle’s law formula can be written as

P_{1 (pa)* } V_{1(m2) }= p2_{(pa)} * V_{2(m2)}

P_{2}= p_{1} * V_{1} / v_{2} or p_{2} /p_{1}= v_{1 }/ V_{2}

P_{1 }and V_{1 } are the initial pressure and volume of the gas

P_{2 }and V_{2} are the final pressure and volume of the gas

P= pressure of the gas

V= volume of the container

### Example:1

Calculate the temperature and quantity of gas are constant? A fixed amount of gas occupies a volume of 4L and exerts a pressure of 500 kpa on the wall of its container. What would be the pressure exerted by the gas on being completely transferred to a new container of volume 4liters.

### Solution:

Given that;

Initial volume V_{1}=4L

Initial pressure p_{1}=500kpa

Final volume v_{2}=4L

As per Boyle’s law p_{1} * V_{1} = p_{2} * V_{2}

p_{2}= p_{1} * V_{1} / V_{2}

p_{2}=500 *4 /4 =500 kpa

Therefore, the gas exterts a pressure of 500kpa on the walls of the 4 liters container.

### Example:2

Calculate the temperature and quantity of gas are constant? A fixed amount of gas occupies a volume of 8L and exerts a pressure of 600 kpa on the wall of its container. What would be the pressure exerted by the gas on being completely transferred to a new container of volume 2liters.

### Solution:

Given that;

Initial volume V_{1}=8L

Initial pressure p_{1}=600kpa

Final volume v_{2}=2L

As per Boyle’s law p_{1} * V_{1} = p_{2} * V_{2}

p_{2}= p_{1} * V_{1} / V_{2}

p_{2}=600 *8 /2 =1200 kpa

Therefore, the gas exterts a pressure of 1200kpa on the walls of the 2 liters container.